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2a^2-6a-140=0
a = 2; b = -6; c = -140;
Δ = b2-4ac
Δ = -62-4·2·(-140)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-34}{2*2}=\frac{-28}{4} =-7 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+34}{2*2}=\frac{40}{4} =10 $
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